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Old 07-27-2008, 05:40 PM
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Joker13 Joker13 is offline
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Join Date: Sep 2006
Location: Somewhere in the USA
Posts: 1,184
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Lets see if I can figure this out

(6 + √10)
(18 - √90) =
(108-√3240 + √3240 - √900)/ d.b. press
y3 - by2 + cy - d = 0, put y = x + b/3 to get

x3 + mx = n where m = c - b2/3, n = d - bc/3 + 2b3/27. (hammer)

-x4 + 2px2 + p2 = px2 - qx - r + p2
i.e.
(x2 + p)2 = px2 - qx - r + p2 (gym with no real equipment)

x3 + 3b2x = 2c3

Put x = (e2 - b2)/e. Then

e6 - 2c3e3 = b6

which is a quadratic in e3, and so can be solved for e3 to get

e3 = c3 +√(b6 + c6).

However

e3(e3 - 2c3) = b6 so that b6/e3 = -c3 +√(b6 + c6).

Got it.
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